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319.95x^2+85.5x-500.96=0
a = 319.95; b = 85.5; c = -500.96;
Δ = b2-4ac
Δ = 85.52-4·319.95·(-500.96)
Δ = 648438.858
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85.5)-\sqrt{648438.858}}{2*319.95}=\frac{-85.5-\sqrt{648438.858}}{639.9} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85.5)+\sqrt{648438.858}}{2*319.95}=\frac{-85.5+\sqrt{648438.858}}{639.9} $
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